x = (-b ± √(b²-4ac)) / (2a)，itsina、b、casPowernumber。

Question 1

What isQuadratic Equation？

Accepted Answer

Quadratic Equationise.g.ax²+bx+c=0'sPower，itsina≠0。PassRootformulax=(-b±√(b²-4ac))/2acanSolve。

Question 2

DiscriminantΔiswhat？

Accepted Answer

DiscriminantΔ=b²-4ac。Δ>0hastwounequalReal roots，Δ=0hasoneheavyRoot，Δ<0hastwotogetherComplex roots。

Question 3

Rootformulaiswhat？

Accepted Answer

x = (-b ± √(b²-4ac)) / (2a)，itsina、b、casPowernumber。